PeterSk":1hiw3yjx said:
You mock but clearly miss the point. It's about the initial starting condition, once the load is moving even at a fraction of full speed the required power to spin it up to full speed drops exponentially.
Yes, I mock, but only because I thought a full explanation a bit esoteric for a workshop forum. Nevertheless, here goes:
The starting transient is made up of two separate components. One is the magnetising current (which is what PeterSk is getting at) and the other is the locked rotor current (which PeterSk has ignored).
Magnetising current:
This applies to all sorts of electric machine (particularly motors and transformers) with an iron core that is magnetised by the electricity supply to the machine. Assuming the core to have no residual magnetism, an increasing voltage on the windings will create a magnetic field in the core of increasing flux. As the voltage is alternating, after 5 mS it will reverse and the flux reduced. After another 10 mS the voltage will be at a negative maximum and the magnetic flux will have reversed.
If the device (and particularly a transformer) is switched off when the magnetic flux is not passing through zero, the core will retain some magnetism when the circuit's switched off. Switching on again may occur when it reinforces the residual magnetism. Then the induced magnetic flux may exceed the capability of the core. The core becomes saturated, the magnetism no longer increases, so the constraint on the voltage no longer occurs (i.e. there's no "back e.m.f."). You then get a very short-lived current transient.
Locked rotor current:
A squirrel cage induction motor (You'd only expect to find this type of induction motor in a home workshop) will run at nearly its synchronous speed when not loaded. That's normally 3000 or 1500 rpm, (from the mains frequency in cycles per minute — 50 cycles * 60 seconds/min = 3000). As the mechanical load is increased, the speed reduces and a current is induced in the rotor of the motor, which creates torque. This torque would bring the motor to a standstill if it did not get electric power to maintain rotation.
If the motor is overloaded mechanically, the speed will fall (typically below 85% of synchronous speed), the power it consumes will rise and eventually trip the overcurrent protection.
When the motor starts, the motor's rotor is stationary and so the motor takes a current that's higher than its full load current. This current does not decrease exponentially. It falls to the FLC when the motor has speeded up to its working speed, around 90% of synchronous speed. The inertia of the motor's rotor plus the intertia of the machenery it's powering will slow the speed-up. If it powers up on load, full load speed could take a few seconds during which a starting current, higher than the full load current, must be supplied.
If the circuit supplying the motor isn't adequate to provide the starting transient, the motor may take too long to speed up; the motor takes a high current for longer and causes the circuit protection to operate (I think that's what is happening to one respondant's 1½ HP motor that blows 13A fuses)
I'm sorry if you think this a bit heavy for the forum; if so, just laugh at the "rotor of the motor" quote from "Hello hello". :lol: