Shultzy
Established Member
I'm trying to get to grips with AV before voting. I've found plenty of places which give a view but without much detail. Just to see if I'm on the right track is this how it works
On the first ballot
Candidate A gets 33 votes
Candidate B gets 31 votes
Candidate C gets 20 votes
Candidate D gets 16 votes
As no candidate has 50% Candidate D is eliminated and their votes are redistributed according to the second preferences, so
Candidate A gets 33 votes + 6 from Candidate D = 39 votes
Candidate B gets 31 votes + 6 from Candidate D = 37 votes
Candidate C gets 20 votes + 4 from Candidate D = 24 votes
As no candidate has 50% Candidate C is eliminated and their votes are redistributed according to the 20 second preferences and 4 third preferences, so
Candidate A gets 33 votes + 6 from Candidate D + 7 from Candidate C= 46 votes
Candidate B gets 31 votes + 6 from Candidate D + 17 from Candidate C= 54 votes
so Candidate B wins.
Now this is only with 4 candidates so its easy to work out, but in the 2010 election theoretically there could have been up to 12 candidates on the ballot paper!
Now I believe we don't have to put all the candidates in order but if you don't express a preference for one of the remaining candidates in the race then the ballot paper is referred to as 'exhausted' and plays no further part in deciding the result.
It seems to me it very complicated to count and prone to mistakes. With an average of 8 candidates per ward that might be 5 redistributions.
Discuss
On the first ballot
Candidate A gets 33 votes
Candidate B gets 31 votes
Candidate C gets 20 votes
Candidate D gets 16 votes
As no candidate has 50% Candidate D is eliminated and their votes are redistributed according to the second preferences, so
Candidate A gets 33 votes + 6 from Candidate D = 39 votes
Candidate B gets 31 votes + 6 from Candidate D = 37 votes
Candidate C gets 20 votes + 4 from Candidate D = 24 votes
As no candidate has 50% Candidate C is eliminated and their votes are redistributed according to the 20 second preferences and 4 third preferences, so
Candidate A gets 33 votes + 6 from Candidate D + 7 from Candidate C= 46 votes
Candidate B gets 31 votes + 6 from Candidate D + 17 from Candidate C= 54 votes
so Candidate B wins.
Now this is only with 4 candidates so its easy to work out, but in the 2010 election theoretically there could have been up to 12 candidates on the ballot paper!
Now I believe we don't have to put all the candidates in order but if you don't express a preference for one of the remaining candidates in the race then the ballot paper is referred to as 'exhausted' and plays no further part in deciding the result.
It seems to me it very complicated to count and prone to mistakes. With an average of 8 candidates per ward that might be 5 redistributions.
Discuss