siggy_7
Full time tool collector, part time woodworker
Yes it does explain that. I should say though that I looked into it after my post and stupidly realised that by the formulae in that document pressure drop is a function of the inlet and outlet diameter, affecting the Euler number by cyclone diameter alone doesn't come into it. To get a sensible pressure drop with your stated flow rate you would need 9" inlet and outlet diameters!
I would say that your estimated flow rates are very high, particularity for a 3hp extractor. Bill Pentz's target flow rate is about half that flow (albeit using a cyclone with a relatively high 6.5" water pressure drop). I would reckon on sticking with the 6" inlet and outlet and a diameter at least 3x and probably approaching 4x the outlet diameter. Also if you cash transition to a tall, thin rectangular inlet with a slightly downward angle I would imagine that would help greatly.
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I would say that your estimated flow rates are very high, particularity for a 3hp extractor. Bill Pentz's target flow rate is about half that flow (albeit using a cyclone with a relatively high 6.5" water pressure drop). I would reckon on sticking with the 6" inlet and outlet and a diameter at least 3x and probably approaching 4x the outlet diameter. Also if you cash transition to a tall, thin rectangular inlet with a slightly downward angle I would imagine that would help greatly.
Sent from my SM-N910F using Tapatalk