Hi Andrew. The hard air flow numbers below rely on interpreting/guesstimating from Bill Pentz's table at middle of this page:
http://billpentz.com/woodworking/cyclone/DCBasics.cfm
Presumably you are exhausting outside to avoid the need to fit a cyclone and fine filters. The cooling effect of drawing in outside air will depend i guess on the temperature of that air, the starting temperature and volume of your shop, and the cfm rate for how long/often the air is being dumped.
One way of looking at it is how fast the air in your shop will be replaced by outside air - divide the volume of the shop in cubic ft (length X breadth X height in ft). So volume in cubic feet/1100 = rough time in minutes to replace the air the shop. (pardon if i'm being too picky)
You can estimate the heat loss in kW using the formula:
Heat loss in Btu/hr = 1.08 X cfm X (room temp deg F - outside air temp deg F)
3412 Btu/hr = 1kW, so divide the answer by 3412 to get the answer in KW.
You probably have a fair feel for how quickly you shop would warm up on say 2kW of heating, so this would give some feel for how fast it might cool.
While i'm fitting a cyclone and HEPA filters that's my plan too - no point clogging your filters if exhausting is causing nobody any problem, and the outside air temperature and humidity conditions allow. That said my shop is fairly large at 8.5X5.5M with a loft overhead. (a decent hot air reservoir) I will have an 8in branch to exhaust outside fitted with a blast gate - when closed it will divert all of the air through the filters.
According to Bill's test tables a 12 inch impeller delivers around 880cfm on 10ft of flex hose with filters and a cyclone. (the high number is the result of a very short hose compared to most ducted installations, add more ducting and it rapidly goes south) He's presumably on 3450rpm 60Hz US motors so you will lose a bit by going to 50Hz in the UK. On the other hand he reckons that 3hp will deliver 1100cfm on a 13 inch impeller, so you have a bit more power. (but check your rpm is 2850)
It's possibly unlikely that the motor is oversized (as in there is less impeller than the motor can handle) on a commercial dust system, and while it probably doesn't do the 3,000m3/hr (1760cfm) on any realistic duct set up it could well do some more than the 880 cfm Bill quotes for a 12 in impeller. (this draws only around 1.5hp) Your coarse filters and no cyclone will save some pressure drop too, as will using smooth ducting as opposed to flex hose per Bill's test. (hose has 3 - 4 X the pressure drop per unit length as galvanised duct.
880cfm is not quite enough to do a really good job he says (it meets chip collection rather than fine dust collection needs), but depending on how you figure the pros and cons above you could easily end up around 1100cfm which if achieved he reckons is fine.
It'd be important to carefully think through the ducting and hose arrangements to minimise the lengths and avoid leaks and restrictions - especially of flexible hose. Also to make sure the machine hoods are not restrictive. i.e. have free area equal to at least 6 in duct. Bill's 10ft of flex hose should be equivalent to about 30ft or a bit more of galvanised ducting - so it'd probably be best to get as far under this as possible.
One test that should i think give a ball park indication of where you are on CFM would be to check the current being drawn by the fan motor while the system is in use and work it back to hp. (240 X amps)/1000 = kW. (approx) Then kW/0.746 = hp.
If it's less than about 2.2hp (as you restrict the intake on a fan the power drawn reduces) it's probably getting a tiny bit marginal on cfm to do the full-on dust clearance job.
Please pardon the mixing of units... :lol: